[Bugs] [Bug 1623593] Run 'make -j<procs>' (parallel, on multiple processors, compilation

[bugzilla at redhat.com]

https://bugzilla.redhat.com/show_bug.cgi?id=1623593

Nigel Babu <nigelb at redhat.com> changed:

           What    |Removed                     |Added
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              Flags|needinfo?(nigelb at redhat.com |
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--- Comment #3 from Nigel Babu <nigelb at redhat.com> ---
I don't know why that's the output shown on the terminal. That seems to have
something to do with the Makefile code. Not the face that we're running it with
make -j $n. On my machine when I run with make -j 4, I still see that line.
That doesn't mean `make -j 4` isn't called by the build scripts.

nigelb at athena  ~/code/glusterfs  make -j 4
(CDPATH="${ZSH_VERSION+.}:" && cd . && /bin/sh
/home/nigelb/code/glusterfs/missing autoheader)
rm -f stamp-h1
touch config.h.in
cd . && /bin/sh ./config.status config.h
config.status: creating config.h
config.status: config.h is unchanged
make --no-print-directory all-recursive
Making all in rpc/xdr/gen
make --no-print-directory all-am

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