[Gluster-users] about heal full

[Krutika Dhananjay]

Yes. 'heal-full' should be executed on the node with the highest uuid.

Here's how i normally figure out what uuid is the highest:
Put all the nodes' uuids in a text file, one per line, sort them and get
the last uuid from the list.

To be more precise:
On any node, you can get the uuids of the peers through `gluster peer
status` output.
Gather them all and put them in a file.
Next, in order to get the uuid of the node where you executed peer status
itself, you use the command `gluster system:: uuid get`
Put this uuid as well into the text file.

Now execute
# cat <text-file-path> | sort

The last uuid printed in this list is the one that corresponds to the
highest uuid in the cluster.

HTH,
Krutika


On Mon, Mar 14, 2016 at 12:49 PM, songxin <songxin_1980 at 126.com> wrote:

> Hi,
> I have create a replicate volume and I want  to run "gluster volume heal
> gv0 full".
>
> I found that if I run "gluster volume heal gv0 full" on one board it
> always output err like below.
>          Launching heal operation to perform full self heal on volume gv0
> has been unsuccessful
>
> But If I run "heal full " on the another board it alway sucessful.
>
> I found the code of glusterfs as  below.
>
>                 if (gf_uuid_compare (brickinfo->uuid, candidate) > 0)
>                         gf_uuid_copy (candidate, brickinfo->uuid);
>
>                 if ((*index) % hxl_children == 0) {
>                         if (!gf_uuid_compare (MY_UUID, candidate)) {
>                                 _add_hxlator_to_dict (dict, volinfo,
>
> ((*index)-1)/hxl_children,
>                                                       (*hxlator_count));
>                                 (*hxlator_count)++;
>                         }
>                         gf_uuid_clear (candidate);
>                 }
>
> My question is below:
> Must I run "heal full" on the board whose uuid is the biggest?
> If so, how cound I know which is the biggest board before I try to run
> "heal full" on every board?
>
> Thanks,
> Xin
>
>
>
>
>
>
>
>
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