[Gluster-users] Replica 3 - how to replace failed node (peer)

[Karthik Subrahmanya]

Hi Strahil,

Thank you for sharing your experience with reset-brick option.
Since he is using the gluster version 3.7.6, we do not have the reset-brick
[1] option implemented there. It is introduced in 3.9.0. He has to go with
replace-brick with the force option if he wants to use the same path & name
for the new brick.
Yes, it is recommended to have the new brick to be of the same size as that
of the other bricks.

[1]
https://docs.gluster.org/en/latest/release-notes/3.9.0/#introducing-reset-brick-command

Regards,
Karthik

On Wed, Apr 10, 2019 at 10:31 PM Strahil <hunter86_bg at yahoo.com> wrote:

> I have used reset-brick - but I have just changed the brick layout.
> You may give it a try, but I guess you need your new brick to have same
> amount of space (or more).
>
> Maybe someone more experienced should share a more sound solution.
>
> Best Regards,
> Strahil NikolovOn Apr 10, 2019 12:42, Martin Toth <snowmailer at gmail.com>
> wrote:
> >
> > Hi all,
> >
> > I am running replica 3 gluster with 3 bricks. One of my servers failed -
> all disks are showing errors and raid is in fault state.
> >
> > Type: Replicate
> > Volume ID: 41d5c283-3a74-4af8-a55d-924447bfa59a
> > Status: Started
> > Number of Bricks: 1 x 3 = 3
> > Transport-type: tcp
> > Bricks:
> > Brick1: node1.san:/tank/gluster/gv0imagestore/brick1
> > Brick2: node2.san:/tank/gluster/gv0imagestore/brick1 <— this brick is
> down
> > Brick3: node3.san:/tank/gluster/gv0imagestore/brick1
> >
> > So one of my bricks is totally failed (node2). It went down and all data
> are lost (failed raid on node2). Now I am running only two bricks on 2
> servers out from 3.
> > This is really critical problem for us, we can lost all data. I want to
> add new disks to node2, create new raid array on them and try to replace
> failed brick on this node.
> >
> > What is the procedure of replacing Brick2 on node2, can someone advice?
> I can’t find anything relevant in documentation.
> >
> > Thanks in advance,
> > Martin
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